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Proof step 6 from proof refine-read-echdr (previous step)

apebs[m2] = mkpeb(aehdr1, avhdr, buf, m1, false), aehdr = aehdr0, m = EB_PAGE_SIZE, m0 = m2, m2 < # apebs, abs(pebs, apebs), mtd-cons(pebs), ubi-io-inv(apebs) ⊦ ⟪if m0 < # pebs ∧ ¬ pebs[m0].bad then let buf = mkbuf(m) in {ubi_io_read#(m0, 0, 0, m, pebs; buf; bitflips, err); if err = ESUCCESS then if isempty(buf) then aehdr := empty else let ehdr = ? in {decode_echeader#(m, buf; ehdr; err); if err = ESUCCESS then aehdr := aechdr(ehdr.ec)}} else abort⟫ ⟨aubi_io_read_echdr#(m2, apebs; aehdr0; isbad, err0)⟩ (aehdr = aehdr0 ∧ (bitflips ↔ isbad) ∧ err = err0)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

Additional information