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Proof step 186 from proof refine-write-data-wl (previous step)

apebs[m1] = mkpeb(aehdr, avhdr, buf0, 0, false), m = EB_PAGE_SIZE, m0 = m1, n = align↑(datasize(buf, n), EB_PAGE_SIZE), aehdr.valid?, avhdr.valid?, m1 < # apebs, abs(pebs, apebs), mtd-cons(pebs), ubi-io-inv(apebs), n ≤ LEB_SIZE, n ≤ # buf, m0 < # pebs → m0 < # pebs ∧ (¬ pebs[m0].bad → m0 < # pebs) ⊦ datasize(buf, n) = 0, m0 < # pebs ∧ ¬ pebs[m0].bad ∧ pebs[m0].fill = 2 * EB_PAGE_SIZE ∧ n ≤ LEB_SIZE ∧ n ≤ # buf ∧ is-aligned(n, EB_PAGE_SIZE)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 187:
apebs[m1] = mkpeb(aehdr, avhdr, buf0, 0, false), n = align↑(datasize(buf, n), EB_PAGE_SIZE), avhdr.valid?, aehdr.valid?, m1 < # pebs, m1 < # apebs, abs(pebs, apebs), mtd-cons(pebs), ubi-io-inv(apebs), n ≤ # buf, n ≤ LEB_SIZE ⊦ datasize(buf, n) = 0, is-aligned(n, EB_PAGE_SIZE) ∧ pebs[m1].fill = 2 * EB_PAGE_SIZE ∧ ¬ pebs[m1].bad

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ abs(pebs, apebs) → ¬ # pebs < # apebs; (s)%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat% ⊦ m < n ↔ ¬ n ≤ m; (ss)