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Proof step 19 from proof refine-write-data-wl (previous step)

pebs[m1] = mkpeb(buf1, 2 * EB_PAGE_SIZE, false), apebs[m1] = mkpeb(aehdr, avhdr, buf0, 0, false), err = ESUCCESS, err = err0, n = align↑(datasize(buf, n), EB_PAGE_SIZE), avhdr.valid?, aehdr.valid?, m1 < # pebs[m1, pebs[m1].data:= copy(buf, 0, pebs[m1].data, 2 * EB_PAGE_SIZE, n)], m1 < # pebs, m1 < # apebs, abs(pebs, apebs), abs-peb(mkpeb(buf1, 2 * EB_PAGE_SIZE, false), mkpeb(aehdr, avhdr, buf0, 0, false)), is-aligned(n, EB_PAGE_SIZE), mtd-cons(pebs), ubi-io-inv(apebs), n ≤ # buf, n ≤ LEB_SIZE, 2 * EB_PAGE_SIZE + n ≤ # pebs[m1].data, 0 + n ≤ # buf, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟨aubi_io_write_data_wl#(m1, n, buf; apebs; err1)⟩ ( abs (pebs[m1, pebs[m1].data:= copy(buf, 0, pebs[m1].data, 2 * EB_PAGE_SIZE, n)] [m1, pebs[m1, pebs[m1].data:= copy(buf, 0, pebs[m1].data, 2 * EB_PAGE_SIZE, n)][m1].fill:= (2 * EB_PAGE_SIZE + n) ], apebs) ∧ err = err1), datasize(buf, n) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
pebs[m1] = mkpeb(buf1, 2 * EB_PAGE_SIZE, false), apebs[m1] = mkpeb(aehdr, avhdr, buf0, 0, false), n = align↑(datasize(buf, n), EB_PAGE_SIZE), datasize(buf, n) ≠ 0, avhdr.valid?, aehdr.valid?, m1 < # pebs, m1 < # apebs, abs(pebs, apebs), abs-peb(mkpeb(buf1, 2 * EB_PAGE_SIZE, false), mkpeb(aehdr, avhdr, buf0, 0, false)), is-aligned(n, EB_PAGE_SIZE), mtd-cons(pebs), ubi-io-inv(apebs), n ≤ # buf, n ≤ LEB_SIZE, 2 * EB_PAGE_SIZE + n ≤ PEB_SIZE ⊦ ⟨aubi_io_write_data_wl#(m1, n, buf; apebs; err1)⟩ (abs(pebs[m1, (pebs[m1].data:= copy(buf, 0, pebs[m1].data, 2 * EB_PAGE_SIZE, n)).fill:= (2 * EB_PAGE_SIZE + n)], apebs) ∧ ESUCCESS = err1)

Rule argument

Additional information

Used simplifier rules: n < # pebs ⊦ pebs[n] = mkpeb(buf, m, boolvar) ∧ mtd-cons(pebs) → # buf = PEB_SIZE; (s)% ⊦ mkpeb(buf, m, boolvar).data = buf; (s)%m < # pebs ⊦ pebs[m, peb][m, peb0] = pebs[m, peb0]; (s)% ⊦ m < n → (n ≤ m ↔ false); (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < # pebs → pebs[m, peb][m] = peb; (s)% ⊦ ¬ ⌊ESUCCESS⌋ ; (s)% ⊦ # pebs[n, peb] = # pebs; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)