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Proof step 101 from proof refine-write-echdr (previous step)

# buf2 = EB_PAGE_SIZE, apebs[m2] = mkpeb(empty, avhdr, buf0, m1, false), pebs[m2] = mkpeb(buf1, 0, false), m2 < # pebs, m2 < # apebs, abs(pebs, apebs), abs-peb(mkpeb(buf1, 0, false), mkpeb(empty, avhdr, buf0, m1, false)), mtd-cons(pebs), ubi-io-inv(apebs), ⌊err1⌋ ⊦ ⟨apebs[m2].echdr := empty⟩ abs(pebs, apebs)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).echdr:= aehdr0 = mkpeb(aehdr0, avhdr, buf, m, boolvar); (s)% ⊦ apebs[n] = apeb → apebs[n, apeb] = apebs; (s)