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Proof step 29 from proof refine-write-vidhdr (previous step)

# buf2 = EB_PAGE_SIZE, apebs[m2] = mkpeb(aehdr, empty, buf0, m1, false), pebs[m2] = mkpeb(buf1, EB_PAGE_SIZE, false), err = ESUCCESS, err = err0, aehdr.valid?, m2 < # pebs[m2, pebs[m2].data:= copy(buf2, 0, pebs[m2].data, EB_PAGE_SIZE, EB_PAGE_SIZE)], m2 < # pebs, m2 < # apebs, abs(pebs, apebs), abs-peb(mkpeb(buf1, EB_PAGE_SIZE, false), mkpeb(aehdr, empty, buf0, m1, false)), is-encoded(vidhdr(v, m6, m5, m3, m4), buf2), mtd-cons(pebs), ubi-io-inv(apebs), EB_PAGE_SIZE + EB_PAGE_SIZE ≤ # pebs[m2].data, 0 + EB_PAGE_SIZE ≤ # buf2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟨aubi_io_write_vidhdr#(m2, avidhdr(v, m6, m5, m3, m4); apebs; err1)⟩ ( abs (pebs[m2, pebs[m2].data:= copy(buf2, 0, pebs[m2].data, EB_PAGE_SIZE, EB_PAGE_SIZE)] [m2, pebs[m2, pebs[m2].data:= copy(buf2, 0, pebs[m2].data, EB_PAGE_SIZE, EB_PAGE_SIZE)][m2].fill:= (2 * EB_PAGE_SIZE) ], apebs) ∧ err = err1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
# buf2 = EB_PAGE_SIZE, apebs[m2] = mkpeb(aehdr, empty, buf0, m1, false), pebs[m2] = mkpeb(buf1, EB_PAGE_SIZE, false), aehdr.valid?, m2 < # pebs, m2 < # apebs, abs(pebs, apebs), abs-peb(mkpeb(buf1, EB_PAGE_SIZE, false), mkpeb(aehdr, empty, buf0, m1, false)), is-encoded(vidhdr(v, m6, m5, m3, m4), buf2), mtd-cons(pebs), ubi-io-inv(apebs), 2 * EB_PAGE_SIZE ≤ PEB_SIZE ⊦ ⟨aubi_io_write_vidhdr#(m2, avidhdr(v, m6, m5, m3, m4); apebs; err1)⟩ (abs(pebs[m2, (pebs[m2].data:= copy(buf2, 0, pebs[m2].data, EB_PAGE_SIZE, EB_PAGE_SIZE)).fill:= (2 * EB_PAGE_SIZE)], apebs) ∧ ESUCCESS = err1)

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m; (s)%n < # pebs ⊦ pebs[n] = mkpeb(buf, m, boolvar) ∧ mtd-cons(pebs) → # buf = PEB_SIZE; (s)% ⊦ mkpeb(buf, m, boolvar).data = buf; (s)%m < # pebs ⊦ pebs[m, peb][m, peb0] = pebs[m, peb0]; (s)% ⊦ m < n → (n ≤ m ↔ false); (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < # pebs → pebs[m, peb][m] = peb; (s)% ⊦ ¬ ⌊ESUCCESS⌋ ; (s)% ⊦ # pebs[n, peb] = # pebs; (s)% ⊦ m + m = 2 * m; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)