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Proof step 28 from proof bag-add-rem-same (previous step)

n0 = n, ∀ n. (∀ n0. count(n0, (bag0 -- n) ++ n) = count(n0, bag0)) ↔ count(n, bag0) ≠ 0 ⊦ 1 + count(n0, bag0 -- n) = count(n0, bag0), count(n, bag0) = 0, n = m, n0 = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
∀ n. (∀ n0. count(n0, (bag0 -- n) ++ n) = count(n0, bag0)) ↔ count(n, bag0) ≠ 0 ⊦ 1 + count(n, bag0 -- n) = count(n, bag0), count(n, bag0) = 0, n = m

Proof step 28 from proof bag-add-rem-same (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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