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Proof step 2 from proof bag-count-addtwice (previous step)

bag = bag0 ++ m ++ m, count(m, bag) = 1 ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: n < n0 ⊦ (* n) ≠ m0 + (* n0); (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ count(n, bag0 ++ n) = count(n, bag0) + 1; (s)