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Proof step 1 from proof bag-diff-one (conclusion)

⊦ bag \ {n} = bag -- n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ {n} = ∅ ++ n
Proof step 3:
⊦ bag \ (∅ ++ n) = bag -- n

Rule argument

spec: bag-union, inst: nat-bag name: one seq: ⊦ {n} = ∅ ++ n subst: [n] → [n] flags: <all paths>

Additional information

Used terms: n