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Proof step 13 from proof bag-rem-notmax (previous step)

m0 < bag0.max, ∀ m. (bag0 -- m).max = bag0.max ∨ m = bag0.max ⊦ (m0 < (bag0 -- m).max ⊃ (bag0 -- m).max;m0) = bag0.max, bag0 = ∅ ++ m, bag0 = ∅, m = bag0.max, m0 = m

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m

Additional information

Used simplifier rules: lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic Used terms: m