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Proof step 9 from proof bag-rem-notmax (previous step)

m0 < bag0.max, ∀ m. (bag0 -- m).max = bag0.max ∨ m = bag0.max ⊦ (m0 = m ⊃ bag0;(bag0 -- m) ++ m0).max = bag0.max, bag0 = ∅, m = bag0.max

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 10:
m0 < bag0.max, ∀ m. (bag0 -- m).max = bag0.max ∨ m = bag0.max ⊦ (m0 = m ⊃ bag0;(bag0 -- m) ++ m0).max = bag0.max, bag0 = ∅, m = bag0.max, m0 = m

Rule argument

fma: m0 = m

Additional information

Used formulas: m0 = m