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Proof step 7 from proof bag-rem-subseteq (previous step)

count(n0, bag) < count(n0, bag) - (n0 = n ∧ count(n0, bag) ≠ 0 ⊃ 1;0) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
count(n0, bag) < count(n0, bag) - (n0 = n ∧ count(n, bag) ≠ 0 ⊃ 1;0) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic