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Proof step 4 from proof bag-remadd-in (previous step)

∀ n. (bag0 -- n) ++ n = (n ∈ bag0 ⊃ bag0;bag0 ++ n) ⊦ (bag0 -- n) ++ m ++ n = (n ∈ bag0 ++ m ⊃ bag0 ++ m;bag0 ++ m ++ n), m = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information