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Proof step 1 from proof max-in-bag (conclusion)

⊦ bag.max ∈ bag ↔ bag ≠ ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ bag = ∅, bag.max ∈ bag

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ n ∈ ∅; (s)