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Proof step 2 from proof max-rem-ls (previous step)

bag.max < (bag -- n).max ⊦ bag -- n = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
bag.max < (bag -- n).max ⊦ bag -- n = ∅

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic