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Proof step 15 from proof max-rem-notsame (previous step)

count((m < bag.max ⊃ bag.max;m), bag ++ m) = 0 ⊦ bag = ∅, count(bag.max, bag) = 0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 16:
count((m < bag.max ⊃ bag.max;m), bag ++ m) = 0, m < bag.max ⊦ bag = ∅, count(bag.max, bag) = 0

Rule argument

fma: m < bag.max

Additional information

Used simplifier rules: ⊦ count(n, bag0 ++ n) = count(n, bag0) + 1; (s)% ⊦ m + n = 0 ↔ m = 0 ∧ n = 0; (ws)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used formulas: m < bag.max