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Proof step 30 from proof max-rem-notsame (previous step)

bag0 = ∅ ++ bag0.max, m < bag0.max ⊦ bag0.max = m, bag0 = ∅, count(bag0.max, bag0) = 1

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: max-one: ⊦ (∅ ++ n).max = n;% ⊦ count(n, ∅ ++ n) = 1; (s)