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Proof step 32 from proof max-rem-notsame (previous step)

bag0.max < m, bag0 = ∅ ++ bag0.max ∨ bag0.max = (bag0 -- bag0.max).max ∨ count(bag0.max, bag0) = 1 ⊦ bag0 = ∅, count(m, bag0) = 0, m = bag0.max

User applied rule weakening

And obtained the following new goals

Proof step 33:
bag0.max < m ⊦ bag0 = ∅, count(m, bag0) = 0

Rule argument

poslist: left 2, right 3

Additional information