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Proof step 39 from proof max-rem-notsame (previous step)

(m0 < bag.max ⊃ bag.max;m0) < m, ∀ m. bag.max < m → bag = ∅ ∨ count(m, bag) = 0 ⊦ bag = ∅, count(m, bag ++ m0) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information