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Proof step 4 from proof max-rem-notsame (previous step)

bag.max = (bag -- n).max, count(bag.max, bag) = 1, n = bag.max ⊦ bag -- n = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
bag.max = (bag -- bag.max).max, count(bag.max, bag) = 1 ⊦ bag -- bag.max = ∅

Rule argument

Additional information