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Proof step 2 from proof unique-elems-addmax (previous step)

unique-elems(bag ++ bag.max) ⊦ bag = ∅

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: unique-elems-add: ⊦ unique-elems(bag ++ m) ↔ unique-elems(bag) ∧ ¬ m ∈ bag;%max-in-bag: ⊦ bag.max ∈ bag ↔ bag ≠ ∅;