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Proof step 3 from proof unique-elems-rem-notin (previous step)

unique-elems(bag) ⊦ m ∈ bag -- n ↔ m ≠ n ∧ m ∈ bag

User applied rule case distinction

And obtained the following new goals

Proof step 4:
unique-elems(bag), m ∈ bag -- n ⊦ m ≠ n ∧ m ∈ bag

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ n ≠ n0 → (n ∈ bag0 -- n0 ↔ n ∈ bag0); (ss)