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Proof step 3 from proof unique-elems-subset (previous step)

unique-elems(bag1), bag0 ⊆ bag1 ⊦ unique-elems(bag0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ unique-elems(bag) ↔ (∀ n. count(n, bag) ≤ 1)
Proof step 5:
bag0 ⊆ bag1, ∀ n. count(n, bag1) ≤ 1 ⊦ unique-elems(bag0)

Rule argument

spec: <toplevel> name: unique-elems seq: ⊦ unique-elems(bag) ↔ (∀ n. count(n, bag) ≤ 1) subst: [bag] → [bag1] flags: <all paths>

Additional information

Used terms: bag1