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Proof step 1 from proof crash-neutral-get-leb-size (conclusion)
ebm-cons(avols), avols ⊆ avols0, ebm-cons(avols) → ebm-cons(avols0) ⊦ ⟨ebm_get_leb_size#(avols; ; n)⟩ (avols ⊆ avols0 ∧ (ebm-cons(avols) → ebm-cons(avols0)))
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
ebm-cons(avols), ebm-cons(avols0), avols ⊆ avols0 ⊦ ⟨ebm_get_leb_size#(avols; ; n)⟩ true
Rule argument
Additional information