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Proof step 4 from proof crash-neutral-get-volume-size (previous step)

ebm-cons(avols0), ebm-cons(avols), v ∈ avols, avols ⊆ avols0 ⊦ ⟨if v ∈ avols then n := # avols[v] else abort⟩ true

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Proof step 5:
ebm-cons(avols), ebm-cons(avols0), v ∈ avols, avols ⊆ avols0 ⊦ ⟨n := # avols[v]⟩ true

Rule argument

pos: right 1

Additional information