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Proof step 10 from proof crash-neutral-recover (previous step)

ebm-cons(avols1), ebm-cons(avols0), avols1 ⊆ avols0 ⊦ ∃ avols. avols ⊆ avols0

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: avols1

Additional information

Used terms: avols1