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Proof step 20 from proof crash-neutral-write (previous step)

avols[v][m2] = mapped(buf0, m), m2 < # avols[v], n0 < n, ebm-cons(avols), ebm-cons(avols0), is-aligned(m1, EB_PAGE_SIZE), is-aligned(n, EB_PAGE_SIZE), is-aligned(n0, EB_PAGE_SIZE), v ∈ avols, m ≤ m1, m1 + n ≤ LEB_SIZE, n + n2 ≤ # buf, avols ⊆ avols0 ⊦ 0 < n ∧ is-aligned(0, EB_PAGE_SIZE) ∧ ⟨if 0 ≠ 0 then avols[v][m2] := mapped(subarray(avols[v][m2].data, 0, m1) + subarray(buf, n2, 0) + mkempbuf(LEB_SIZE - m1 - 0), m1 + 0)⟩ (avols ⊆ avols0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
avols[v][m2] = mapped(buf0, m), n0 < n, m2 < # avols[v], ebm-cons(avols0), ebm-cons(avols), is-aligned(n0, EB_PAGE_SIZE), is-aligned(n, EB_PAGE_SIZE), is-aligned(m1, EB_PAGE_SIZE), v ∈ avols, n + n2 ≤ # buf, m1 + n ≤ LEB_SIZE, m ≤ m1, avols ⊆ avols0 ⊦ ⟨skip⟩ true

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)%n ≠ 0 ⊦ is-aligned(0, n); (s)% ⊦ EB_PAGE_SIZE ≠ 0; (s)% ⊦ m < n → n ≠ 0; (s)% ⊦ 0 < m ↔ m ≠ 0; (s)