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Proof step 11 from proof inv-change (previous step)

m < # avols[v], ebm-cons(avols), is-aligned(n, EB_PAGE_SIZE), v ∈ avols, n ≤ LEB_SIZE, n ≤ # buf, avols[v][m].mapped? → # avols[v][m].data = LEB_SIZE ∧ avols[v][m].fill ≤ LEB_SIZE ∧ is-aligned(avols[v][m].fill, EB_PAGE_SIZE) ∧ range=(avols[v][m].data, avols[v][m].fill, emptyleb, 0, LEB_SIZE - avols[v][m].fill) ⊦ range=(subarray(buf, 0, n) + mkempbuf(LEB_SIZE - n), n, emptyleb, 0, LEB_SIZE - n)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
LEB_SIZE = n0 + n, m < # avols[v], ebm-cons(avols), is-aligned(n, EB_PAGE_SIZE), v ∈ avols, n ≤ # buf, n ≤ LEB_SIZE, avols[v][m].mapped? → # avols[v][m].data = LEB_SIZE ∧ avols[v][m].fill ≤ LEB_SIZE ∧ is-aligned(avols[v][m].fill, EB_PAGE_SIZE) ∧ range=(avols[v][m].data, avols[v][m].fill, emptyleb, 0, LEB_SIZE - avols[v][m].fill) ⊦ range=(subarray(buf, 0, n) + mkempbuf(n0), n, emptyleb, 0, n0)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [LEB_SIZE, n, n0]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: LEB_SIZE, n, n0