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Proof step 10 from proof inv-erase (previous step)

m < # avols[v], ebm-cons(avols), v ∈ avols, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪skip or avols[v][m] := unmapped⟫ ebm-cons(avols), err0 = ESUCCESS

Heuristic conditional right split applied rule or split right

And obtained the following new goals

Rule argument

Additional information