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Proof step 2 from proof inv-erase (previous step)

m < # avols[v], ebm-cons(avols), v ∈ avols ⊦ ⟪ebm_erase#(v, m; avols; err)⟫ ebm-cons(avols)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m < # avols[v], ebm-cons(avols), v ∈ avols ⊦ ⟪ebm_erase#(v, m; avols; err)⟫ ebm-cons(avols)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic