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Proof step 3 from proof inv-format (previous step)

⊦ ⟪fail_or_success#(; ; err); if err = ESUCCESS then avols := ∅ else avols := ?⟫ (err = ESUCCESS → ebm-cons(avols))

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 4:
⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then avols := ∅ else avols := ?⟫ (err = ESUCCESS → ebm-cons(avols))

Rule argument

pos: right 1

Additional information

Used simplifier rules: fail_or_success#(; ; ERR) {choose ERR0 with ⌊ERR0⌋ ∨ ERR0 = ESUCCESS in ERR := ERR0};