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Proof step 5 from proof inv-format (previous step)

⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then avols := ∅ else avols := ?⟫ (err = ESUCCESS → ebm-cons(avols))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

Additional information