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Proof step 5 from proof inv-recover (previous step)

avols = avols0, ebm-cons(avols1), ebm-cons(avols0), avols1 ⊆ avols0 ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err ≠ ESUCCESS then avols := ?⟫ (err = ESUCCESS → ebm-cons(avols))

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 6:
avols = avols0, ebm-cons(avols0), ebm-cons(avols1), avols1 ⊆ avols0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err ≠ ESUCCESS then avols := ?⟫ (err = ESUCCESS → ebm-cons(avols))
Proof step 10:
avols = avols0, ebm-cons(avols0), ebm-cons(avols1), avols1 ⊆ avols0 ⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 5 from proof inv-recover (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information