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Proof step 5 from proof inv-unmap (previous step)

m < # avols[v], ebm-cons(avols), v ∈ avols ⊦ ⟪avols[v][m] := unmapped⟫ ebm-cons(avols)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ v ∈ avols ∧ m < # avols[v] ∧ ebm-cons(avols) → ( ebm-cons(avols[v, avols[v][m, leb]]) ↔ valid-leb(avols[v][m]) → valid-leb(leb)); (ss)%⊦ valid-leb(leb) ↔ leb.mapped? → # leb.data = LEB_SIZE ∧ leb.fill ≤ LEB_SIZE ∧ is-aligned(leb.fill, EB_PAGE_SIZE) ∧ range=(leb.data, leb.fill, emptyleb, 0, LEB_SIZE - leb.fill); (s)% ⊦ ¬ unmapped.mapped?; (s)