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Proof step 78 from proof inv-write (previous step)

m2 < # avols[v], ebm-cons(avols), is-aligned(n, EB_PAGE_SIZE), is-aligned(m1, EB_PAGE_SIZE), v ∈ avols, n + n2 ≤ # buf, m1 + n ≤ LEB_SIZE, avols[v][m2].mapped? → avols[v][m2].fill ≤ m1, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if n ≠ 0 then avols[v][m2] := unmapped⟫ ebm-cons(avols), err0 = ESUCCESS, avols[v][m2].mapped?

Heuristic conditional right split applied rule if right

And obtained the following new goals

Proof step 79:
m2 < # avols[v], ebm-cons(avols), is-aligned(m1, EB_PAGE_SIZE), is-aligned(n, EB_PAGE_SIZE), v ∈ avols, m1 + n ≤ LEB_SIZE, n + n2 ≤ # buf, avols[v][m2].mapped? → avols[v][m2].fill ≤ m1, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪avols[v][m2] := unmapped⟫ ebm-cons(avols), err0 = ESUCCESS, n = 0, avols[v][m2].mapped?
Proof step 80:
n = 0, m2 < # avols[v], ebm-cons(avols), is-aligned(m1, EB_PAGE_SIZE), is-aligned(n, EB_PAGE_SIZE), v ∈ avols, m1 + n ≤ LEB_SIZE, n + n2 ≤ # buf, avols[v][m2].mapped? → avols[v][m2].fill ≤ m1, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪skip⟫ ebm-cons(avols), err0 = ESUCCESS, avols[v][m2].mapped?

Rule argument

pos: right 1

Proof step 78 from proof inv-write (previous step)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

Additional information