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Proof step 19 from proof ebm-order-antisym (previous step)

# avols1[v] = # avols0[v], unmapped = avols0[v][n], n < # avols0[v], v ∈ avols0, v ∈ avols1 ⊦ avols1[v][n] = erased, unmapped = avols1[v][n], avols1[v][n].mapped?

User applied rule structural induction

And closed the goal!

Rule argument

term: avols1[v][n]

Additional information

Used simplifier rules: leb freely generated by unmapped, erased, mapped;;% ⊦ erased ≠ mapped(buf, m); (s)% ⊦ unmapped ≠ mapped(buf, m); (s)% ⊦ mapped(buf, m).mapped?; (s)