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Proof step 11 from proof ebm-order-trans (previous step)

# avols0[v] = # avols1[v], # avols[v] = # avols1[v], m < # avols1[v], v ∈ avols0, v ∈ avols1, v ∈ avols, avols[v][m] = erased → avols0[v][m] = erased, avols[v][m].mapped? → avols0[v][m] = avols[v][m], avols0[v][m] ≠ unmapped → (avols0[v][m] = erased → avols1[v][m] = erased) ∧ (avols0[v][m].mapped? → avols1[v][m] = avols0[v][m]) ⊦ avols[v][m] = unmapped, (avols[v][m] = erased → avols1[v][m] = erased) ∧ (avols[v][m].mapped? → avols1[v][m] = avols[v][m])

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 2

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