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Proof step 11 from proof ebm-order-write-same (previous step)

# avols0[v] = # avols1[v], m0 < # avols1[v], v ∈ avols1, v ∈ avols0, ∀ m. m < # avols1[v] ∧ avols0[v][m] ≠ unmapped → (avols0[v][m] = erased → avols1[v][m] = erased) ∧ (avols0[v][m].mapped? → avols1[v][m] = avols0[v][m]) ⊦ avols0[v][m0] = unmapped, m0 = m, (avols0[v][m0] = erased → avols1[v][m0] = erased) ∧ (avols0[v][m0].mapped? → avols1[v][m0] = avols0[v][m0])

User applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: m0 abort: F discard: T computed: F

Additional information

Used terms: m0