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Proof step 2 from proof eq-entry-in-lref-in (previous step)

eq-entry(n, v × m) ∈ q ⊦ v × m ∈ q.lebrefs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
eq-entry(n, v × m) ∈ q ⊦ ∃ n. eq-entry(n, v × m) ∈ q

Rule argument

Additional information

Used simplifier rules: in-vl-in-lebrefs: ⊦ lref ∈ q0.lebrefs ↔ lref ∈ q0 ∧ lref ≠ none;%queue-in-vl: ⊦ lref ∈ q ↔ (∃ n. eq-entry(n, lref) ∈ q);% ⊦ none ≠ v × m; (s)