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Proof step 6 from proof in-prepend-other (previous step)

eqent = eq-entry(m, lref0), eqent ∈ q ⊦ eqent = eq-entry(n0, lref), m = n0, ∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information