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Proof step 11 from proof in-rm-v-same (previous step)

eq-entry(n, v × m) ∈ (lref.vol = v ⊃ q0 - lref.vol;eq-entry(m0, lref) ' + (q0 - v)), ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦ lref = none

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
lref = v0 × m1, eq-entry(n, v × m) ∈ (v0 = v ⊃ q0 - v0;eq-entry(m0, lref) ' + (q0 - v)), ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦ lref = none

Rule argument

spec: lebref name: elim seq: ⊦ lref ≠ none → (v = lref.vol ∧ m = lref.leb ↔ lref = v × m) subst: [lref, v, m] → [lref, v0, m1]

Additional information

Used simplifier rules: ⊦ lref ≠ none → (v = lref.vol ∧ m = lref.leb ↔ lref = v × m); (elim) Used terms: lref, v0, m1