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Proof step 3 from proof in-rm-v-same (previous step)

eq-entry(n, v × m) ∈ q - v ⊦

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 4:
eq-entry(n, v × m) ∈ eqent + q0 - v, ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦

Rule argument

term: q

Additional information

Used simplifier rules: queue-rm-v-base: ⊦ [] - v = [];%queue freely generated by [], +;;% ⊦ ¬ eqent ∈ []; (s)