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Proof step 8 from proof in-rm-v-same (previous step)

lref = none, eq-entry(n, v × m) ∈ (lref ≠ none ∧ lref.vol = v ⊃ q0 - lref.vol;eq-entry(m0, lref) ' + (q0 - v)), ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
eq-entry(n, v × m) ∈ q0 - v, ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦ eq-entry(n, v × m) = eq-entry(m0, none)

Rule argument

Additional information

Used simplifier rules: ⊦ none ≠ v × m; (s)% ⊦ eq-entry(m, lref) = eq-entry(m0, lref0) ↔ m = m0 ∧ lref = lref0; (ws)%a: ⊦ (q + q0) + q1 = q + q0 + q1; from specification list[erasequeue-base]% ⊦ eqent ∈ eqent0 ' + q ↔ eqent = eqent0 ∨ eqent ∈ q; (s)