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Proof step 14 from proof in-rm-v (previous step)

eq-entry(m, lref) ∈ q0 - v, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eq-entry(m0, none) ∨ eqent0 ∈ q0), eq-entry(m0, none).pnum = m ∧ (eq-entry(m0, none) = eq-entry(m0, none) ∨ eq-entry(m0, none) ∈ q0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
eq-entry(m, lref) ∈ q0 - v, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ m0 = m, ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eq-entry(m0, none) ∨ eqent0 ∈ q0)

Rule argument

Additional information

Used simplifier rules: ⊦ eq-entry(m, lref).pnum = m; (s)