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Proof step 19 from proof in-rm-v (previous step)

eq-entry(m1, lref0) ∈ q0, eq-entry(m1, lref) ∈ q0 - v, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ m0 = m1, ∃ eqent0. eqent0.pnum = m1 ∧ (eqent0 = eq-entry(m0, none) ∨ eqent0 ∈ q0)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: eq-entry(m1, lref0)

Additional information

Used simplifier rules: ⊦ eq-entry(m, lref).pnum = m; (s) Used terms: eq-entry(m1, lref0)