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Proof step 24 from proof in-rm-v (previous step)

lref0 = v0 × m1, eq-entry(m, lref) ∈ (v0 = v ⊃ q0 - v0;eq-entry(m0, lref0) ' + (q0 - v)), ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ lref0 = none, ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eq-entry(m0, lref0) ∨ eqent0 ∈ q0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
eq-entry(m, lref) ∈ (v0 = v ⊃ q0 - v;eq-entry(m0, v0 × m1) ' + (q0 - v)), ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eq-entry(m0, v0 × m1) ∨ eqent0 ∈ q0)

Rule argument

Additional information

Used simplifier rules: ⊦ none ≠ v × m; (s)