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Proof step 27 from proof in-rm-v (previous step)

eq-entry(m, lref) ∈ q0 - v, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eq-entry(m0, v × m1) ∨ eqent0 ∈ q0)

Heuristic quantifier applied rule exists right

And obtained the following new goals

Proof step 28:
eq-entry(m, lref) ∈ q0 - v, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eq-entry(m0, v × m1) ∨ eqent0 ∈ q0), eq-entry(m0, v × m1).pnum = m ∧ (eq-entry(m0, v × m1) = eq-entry(m0, v × m1) ∨ eq-entry(m0, v × m1) ∈ q0)

Rule argument

pos: right 1 terms: eq-entry(m0, v × m1)

Additional information

Used terms: eq-entry(m0, v × m1)