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Proof step 41 from proof in-rm-v (previous step)

eqent ∈ q0, eq-entry(eqent.pnum, lref) ∈ q0 - v, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ m0 = eqent.pnum, v0 = v, ∃ eqent0. eqent0.pnum = eqent.pnum ∧ (eqent0 = eq-entry(m0, v0 × m1) ∨ eqent0 ∈ q0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 42:
eqent = eq-entry(m2, lref0), eq-entry(m2, lref) ∈ q0 - v, eqent ∈ q0, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ m0 = m2, v0 = v, ∃ eqent0. eqent0.pnum = m2 ∧ (eqent0 = eq-entry(m0, v0 × m1) ∨ eqent0 ∈ q0)

Rule argument

spec: erasequeueentry name: elim seq: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref) subst: [eqent, m, lref] → [eqent, m2, lref0]

Additional information

Used simplifier rules: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref); (elim) Used terms: eqent, m2, lref0