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Proof step 45 from proof in-rm-v (previous step)

∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ v0 = v, eq-entry(m0, v0 × m1) ∈ q0 - v, ∃ eqent. eqent.pnum = m0 ∧ (eqent = eq-entry(eqent.pnum, v0 × m1) ∨ eqent ∈ q0)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: eq-entry(m0, v0 × m1)

Additional information

Used simplifier rules: ⊦ eq-entry(m, lref).pnum = m; (s) Used terms: eq-entry(m0, v0 × m1)