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Proof step 5 from proof in-rm-v (previous step)

eq-entry(m, lref) ∈ q - v ⊦ ∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 6:
eq-entry(m, lref) ∈ eqent + q0 - v, ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ ∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ eqent + q0

Rule argument

term: q

Additional information

Used simplifier rules: queue-rm-v-base: ⊦ [] - v = [];%queue freely generated by [], +;;% ⊦ ¬ eqent ∈ []; (s)