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Proof step 7 from proof in-rm-v (previous step)

eq-entry(m, lref) ∈ (eqent.lebref ≠ none ∧ eqent.lebref.vol = v ⊃ q0 - eqent.lebref.vol;eqent ' + (q0 - v)), ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eqent ∨ eqent0 ∈ q0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
eqent = eq-entry(m0, lref0), eq-entry(m, lref) ∈ (lref0 ≠ none ∧ lref0.vol = v ⊃ q0 - lref0.vol;eqent ' + (q0 - v)), ∀ m, lref, v. eq-entry(m, lref) ∈ q0 - v → (∃ eqent0. eqent0.pnum = m ∧ eqent0 ∈ q0) ⊦ ∃ eqent0. eqent0.pnum = m ∧ (eqent0 = eqent ∨ eqent0 ∈ q0)

Rule argument

spec: erasequeueentry name: elim seq: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref) subst: [eqent, m, lref] → [eqent, m0, lref0]

Additional information

Used simplifier rules: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref); (elim) Used terms: eqent, m0, lref0